A Best Way To Crack Gorenment Job Exams

Civil Engineering Objective Questions { Estimating And Costing }



64. Pick up the correct statement from the following :
A. In order to check up the average depth of excavation, 'Dead mans' are left at the mid-widths of borrow pits
B. The earthwork calculation in excavation is made from the difference in levels obtained with a level
C. The earth work in excavation to form the road embankment includes the formation of correct profile and depositing the soil in layers
D. All the above.

65. Pick up the incorrect statement from the following :
A. Lead is the average horizontal straight distance between the borrow pit and the place of spreading soil
B. The lead is calculated for each block of the excavated area
C. The unit of lead is 50 m for a distance upto 500 m
D. The unit of lead is 1 km where the lead exceeds 2 km.

66. The cross-sections for a highway is taken at
A. right angle to the centre line
B. 30 metres apart
C. intermediate points having abrupt change in gradient
D. All the above.

67.  If B is the width of formation, d is the height of the embankment, side slope S : 1, for a highway with no transverse slope, the area of cross-section is
A. B d Sd
B. Bd Sd2
C. B x ? Sd1/2
D. ?1 (Bd + Sd2).

68.  If the formation level of a highway has a uniform gradient for a particular length, and the ground is also having a longitudinal slope, the earthwork may be calculated by
A. Mid-section formula
B. Trapezoidal formula
C. Prismoidal formula
D. All the above.

69. In the mid-section formula
A. The mean depth is the average of depths of two consecutive sections
B. The area of mid-sections is calculated by using mean depth
C. The volume of the earth work is calculated by multiplying the mid-section area by the distance between the two sections
D. (a), (b) and (c) of the above.

70.  The assumption on which the trapezoidal formula for volumes is based, is
A. The end sections are parallel planes
B. The mid-area of a pyramid is half the average area of the ends
C. The volume of the prismoidal is over-estimted and hence a prismoidal correction is applied
D. All the above.

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